Base | Representation |
---|---|
bin | 11000000001111000… |
… | …11010110010110001 |
3 | 1020022002000111201022 |
4 | 30000330122302301 |
5 | 202410042142043 |
6 | 5532043345225 |
7 | 634456324451 |
oct | 140074326261 |
9 | 36262014638 |
10 | 12900740273 |
11 | 552014a123 |
12 | 2600522215 |
13 | 12a795a135 |
14 | 8a54cbd61 |
15 | 507896868 |
hex | 300f1acb1 |
12900740273 has 4 divisors (see below), whose sum is σ = 13461642048. Its totient is φ = 12339838500.
The previous prime is 12900740249. The next prime is 12900740291. The reversal of 12900740273 is 37204700921.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12900740273 - 232 = 8605772977 is a prime.
It is a super-2 number, since 2×129007402732 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12900740873) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 280450853 + ... + 280450898.
It is an arithmetic number, because the mean of its divisors is an integer number (3365410512).
Almost surely, 212900740273 is an apocalyptic number.
It is an amenable number.
12900740273 is a deficient number, since it is larger than the sum of its proper divisors (560901775).
12900740273 is an equidigital number, since it uses as much as digits as its factorization.
12900740273 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 560901774.
The product of its (nonzero) digits is 21168, while the sum is 35.
The spelling of 12900740273 in words is "twelve billion, nine hundred million, seven hundred forty thousand, two hundred seventy-three".
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