Base | Representation |
---|---|
bin | 111100000111100000… |
… | …1000010011001111001 |
3 | 110100020021012201122211 |
4 | 1320033001002121321 |
5 | 4103344320332423 |
6 | 135150321215121 |
7 | 12220145650513 |
oct | 1701701023171 |
9 | 410207181584 |
10 | 129100949113 |
11 | 4a82a135974 |
12 | 2102b7914a1 |
13 | c235851166 |
14 | 6369d18bb3 |
15 | 3558e7310d |
hex | 1e0f042679 |
129100949113 has 4 divisors (see below), whose sum is σ = 129105776548. Its totient is φ = 129096121680.
The previous prime is 129100949063. The next prime is 129100949137. The reversal of 129100949113 is 311949001921.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 70465295209 + 58635653904 = 265453^2 + 242148^2 .
It is a cyclic number.
It is not a de Polignac number, because 129100949113 - 29 = 129100948601 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (129100941113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2373378 + ... + 2427163.
It is an arithmetic number, because the mean of its divisors is an integer number (32276444137).
Almost surely, 2129100949113 is an apocalyptic number.
It is an amenable number.
129100949113 is a deficient number, since it is larger than the sum of its proper divisors (4827435).
129100949113 is an equidigital number, since it uses as much as digits as its factorization.
129100949113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4827434.
The product of its (nonzero) digits is 17496, while the sum is 40.
The spelling of 129100949113 in words is "one hundred twenty-nine billion, one hundred million, nine hundred forty-nine thousand, one hundred thirteen".
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