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12911069233 = 83155555051
BaseRepresentation
bin11000000011000111…
…10100100000110001
31020022210110021101101
430001203310200301
5202420213203413
65533053004401
7634643164156
oct140143644061
936283407341
1012911069233
115525a64457
122603a83701
1312a9b3564a
148a6a1a22d
15508736edd
hex3018f4831

12911069233 has 4 divisors (see below), whose sum is σ = 13066624368. Its totient is φ = 12755514100.

The previous prime is 12911069231. The next prime is 12911069263. The reversal of 12911069233 is 33296011921.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12911069233 - 21 = 12911069231 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12911069192 and 12911069201.

It is not an unprimeable number, because it can be changed into a prime (12911069231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 77777443 + ... + 77777608.

It is an arithmetic number, because the mean of its divisors is an integer number (3266656092).

Almost surely, 212911069233 is an apocalyptic number.

It is an amenable number.

12911069233 is a deficient number, since it is larger than the sum of its proper divisors (155555135).

12911069233 is an equidigital number, since it uses as much as digits as its factorization.

12911069233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 155555134.

The product of its (nonzero) digits is 17496, while the sum is 37.

The spelling of 12911069233 in words is "twelve billion, nine hundred eleven million, sixty-nine thousand, two hundred thirty-three".

Divisors: 1 83 155555051 12911069233