Base | Representation |
---|---|
bin | 10010111000000100111… |
… | …101110101001011101001 |
3 | 11121000012112212022121201 |
4 | 102320010331311023221 |
5 | 132223042320101443 |
6 | 2431524134204201 |
7 | 162500630215606 |
oct | 22700475651351 |
9 | 4530175768551 |
10 | 1297163440873 |
11 | 46013aa44353 |
12 | 18b4954b3661 |
13 | 954255398a1 |
14 | 46ad69696ad |
15 | 23b1edb834d |
hex | 12e04f752e9 |
1297163440873 has 4 divisors (see below), whose sum is σ = 1297588882900. Its totient is φ = 1296737998848.
The previous prime is 1297163440861. The next prime is 1297163440877. The reversal of 1297163440873 is 3780443617921.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 267043998169 + 1030119442704 = 516763^2 + 1014948^2 .
It is a cyclic number.
It is not a de Polignac number, because 1297163440873 - 217 = 1297163309801 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1297163440877) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 212716440 + ... + 212722537.
It is an arithmetic number, because the mean of its divisors is an integer number (324397220725).
Almost surely, 21297163440873 is an apocalyptic number.
It is an amenable number.
1297163440873 is a deficient number, since it is larger than the sum of its proper divisors (425442027).
1297163440873 is an equidigital number, since it uses as much as digits as its factorization.
1297163440873 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 425442026.
The product of its (nonzero) digits is 6096384, while the sum is 55.
The spelling of 1297163440873 in words is "one trillion, two hundred ninety-seven billion, one hundred sixty-three million, four hundred forty thousand, eight hundred seventy-three".
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