1300000424401 has 4 divisors (see below), whose sum is σ = 1485714770752. Its totient is φ = 1114286078052.

The previous prime is 1300000424381. The next prime is 1300000424413. The reversal of 1300000424401 is 1044240000031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1300000424401 - 2¹⁵ = 1300000391633 is a prime.

It is a super-2 number, since 2×1300000424401² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1300000424461) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 92857173165 + ... + 92857173178.

It is an arithmetic number, because the mean of its divisors is an integer number (371428692688).

Almost surely, 2^{1300000424401} is an apocalyptic number.

It is an amenable number.

1300000424401 is a deficient number, since it is larger than the sum of its proper divisors (185714346351).

1300000424401 is an equidigital number, since it uses as much as digits as its factorization.

1300000424401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 185714346350.

The product of its (nonzero) digits is 384, while the sum is 19.

Adding to 1300000424401 its reverse (1044240000031), we get a palindrome (2344240424432).

The spelling of 1300000424401 in words is "one trillion, three hundred billion, four hundred twenty-four thousand, four hundred one".