Base | Representation |
---|---|
bin | 11101100011110000001001… |
… | …001011001011100000101011 |
3 | 122001021220022010120202020202 |
4 | 131203300021023023200223 |
5 | 114014410424323303003 |
6 | 1140253140051542415 |
7 | 36245130512055311 |
oct | 3543601113134053 |
9 | 561256263522222 |
10 | 130000224041003 |
11 | 38470870410588 |
12 | 126b6ab7bbaa0b |
13 | 576cc78b09024 |
14 | 2416089c3c0b1 |
15 | 100690e0a1088 |
hex | 763c092cb82b |
130000224041003 has 8 divisors (see below), whose sum is σ = 130755232918800. Its totient is φ = 129247333001248.
The previous prime is 130000224040993. The next prime is 130000224041111. The reversal of 130000224041003 is 300140422000031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130000224041003 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130000224061003) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 529336388 + ... + 529581921.
It is an arithmetic number, because the mean of its divisors is an integer number (16344404114850).
Almost surely, 2130000224041003 is an apocalyptic number.
130000224041003 is a deficient number, since it is larger than the sum of its proper divisors (755008877797).
130000224041003 is a wasteful number, since it uses less digits than its factorization.
130000224041003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1058919021.
The product of its (nonzero) digits is 576, while the sum is 20.
Adding to 130000224041003 its reverse (300140422000031), we get a palindrome (430140646041034).
The spelling of 130000224041003 in words is "one hundred thirty trillion, two hundred twenty-four million, forty-one thousand, three".
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