130000312113 has 16 divisors (see below), whose sum is σ = 203449653120. Its totient is φ = 72278165376.

The previous prime is 130000312097. The next prime is 130000312147. The reversal of 130000312113 is 311213000031.

It is not a de Polignac number, because 130000312113 - 2⁴ = 130000312097 is a prime.

It is a super-2 number, since 2×130000312113² (a number of 23 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 130000312092 and 130000312101.

It is not an unprimeable number, because it can be changed into a prime (130000312163) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 83654508 + ... + 83656061.

It is an arithmetic number, because the mean of its divisors is an integer number (12715603320).

Almost surely, 2^130000312113 is an apocalyptic number.

It is an amenable number.

130000312113 is a deficient number, since it is larger than the sum of its proper divisors (73449341007).

130000312113 is a wasteful number, since it uses less digits than its factorization.

130000312113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 167310616.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 130000312113 its reverse (311213000031), we get a palindrome (441213312144).

The spelling of 130000312113 in words is "one hundred thirty billion, three hundred twelve thousand, one hundred thirteen".