Search a number
-
+
130001020033 = 1271213843883
BaseRepresentation
bin111100100010010101…
…0100010010010000001
3110102112222212001211211
41321010222202102001
54112220230120113
6135415513010121
712251355303133
oct1710452422201
9412488761754
10130001020033
1150151206535
12212410b3941
13c34a170bc1
146413693053
1535aceb5b3d
hex1e44aa2481

130001020033 has 8 divisors (see below), whose sum is σ = 131132822528. Its totient is φ = 128870907984.

The previous prime is 130001020027. The next prime is 130001020063. The reversal of 130001020033 is 330020100031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130001020033 - 217 = 130000888961 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130001019995 and 130001020022.

It is not an unprimeable number, because it can be changed into a prime (130001020063) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 267891 + ... + 575992.

It is an arithmetic number, because the mean of its divisors is an integer number (16391602816).

Almost surely, 2130001020033 is an apocalyptic number.

It is an amenable number.

130001020033 is a deficient number, since it is larger than the sum of its proper divisors (1131802495).

130001020033 is a wasteful number, since it uses less digits than its factorization.

130001020033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 845223.

The product of its (nonzero) digits is 54, while the sum is 13.

Adding to 130001020033 its reverse (330020100031), we get a palindrome (460021120064).

The spelling of 130001020033 in words is "one hundred thirty billion, one million, twenty thousand, thirty-three".

Divisors: 1 127 1213 154051 843883 107173141 1023630079 130001020033