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130001310411 = 376190538591
BaseRepresentation
bin111100100010010101…
…1101001001011001011
3110102120000101211011120
41321010223221023023
54112220313413121
6135415523130323
712251360622540
oct1710453511313
9412500354146
10130001310411
1150151394715
12212412139a3
13c34a24311b
14641372abc7
1535ad021bc6
hex1e44ae92cb

130001310411 has 8 divisors (see below), whose sum is σ = 198097234944. Its totient is φ = 74286463080.

The previous prime is 130001310391. The next prime is 130001310431. The reversal of 130001310411 is 114013100031.

It is an interprime number because it is at equal distance from previous prime (130001310391) and next prime (130001310431).

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 130001310411 - 217 = 130001179339 is a prime.

It is not an unprimeable number, because it can be changed into a prime (130001310431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3095269275 + ... + 3095269316.

It is an arithmetic number, because the mean of its divisors is an integer number (24762154368).

Almost surely, 2130001310411 is an apocalyptic number.

130001310411 is a deficient number, since it is larger than the sum of its proper divisors (68095924533).

130001310411 is an equidigital number, since it uses as much as digits as its factorization.

130001310411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6190538601.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 130001310411 its reverse (114013100031), we get a palindrome (244014410442).

The spelling of 130001310411 in words is "one hundred thirty billion, one million, three hundred ten thousand, four hundred eleven".

Divisors: 1 3 7 21 6190538591 18571615773 43333770137 130001310411