1300013223131 has 4 divisors (see below), whose sum is σ = 1485729397872. Its totient is φ = 1114297048392.

The previous prime is 1300013223101. The next prime is 1300013223161. The reversal of 1300013223131 is 1313223100031.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1300013223101) and next prime (1300013223161).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1300013223131 is a prime.

It is a super-2 number, since 2×1300013223131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1300013223101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 92858087360 + ... + 92858087373.

It is an arithmetic number, because the mean of its divisors is an integer number (371432349468).

Almost surely, 2^{1300013223131} is an apocalyptic number.

1300013223131 is a deficient number, since it is larger than the sum of its proper divisors (185716174741).

1300013223131 is an equidigital number, since it uses as much as digits as its factorization.

1300013223131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 185716174740.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 1300013223131 its reverse (1313223100031), we get a palindrome (2613236323162).

The spelling of 1300013223131 in words is "one trillion, three hundred billion, thirteen million, two hundred twenty-three thousand, one hundred thirty-one".