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130001433 = 343333811
BaseRepresentation
bin1111011111110…
…10101000011001
3100001121202102220
413233322220121
5231240021213
620522214253
73135664632
oct757725031
9301552386
10130001433
1167423001
1237654389
1320c19333
14133a0889
15b62de23
hex7bfaa19

130001433 has 4 divisors (see below), whose sum is σ = 173335248. Its totient is φ = 86667620.

The previous prime is 130001429. The next prime is 130001449. The reversal of 130001433 is 334100031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130001433 - 22 = 130001429 is a prime.

It is not an unprimeable number, because it can be changed into a prime (130001423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21666903 + ... + 21666908.

It is an arithmetic number, because the mean of its divisors is an integer number (43333812).

Almost surely, 2130001433 is an apocalyptic number.

It is an amenable number.

130001433 is a deficient number, since it is larger than the sum of its proper divisors (43333815).

130001433 is an equidigital number, since it uses as much as digits as its factorization.

130001433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43333814.

The product of its (nonzero) digits is 108, while the sum is 15.

The square root of 130001433 is about 11401.8170920253. The cubic root of 130001433 is about 506.5815632589.

Adding to 130001433 its reverse (334100031), we get a palindrome (464101464).

The spelling of 130001433 in words is "one hundred thirty million, one thousand, four hundred thirty-three".

Divisors: 1 3 43333811 130001433