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1300021013003 = 1936735860171
BaseRepresentation
bin10010111010101111010…
…010100110101000001011
311121021120200220000122112
4102322233102212220023
5132244420334404003
62433115454012535
7162631506166646
oct22725722465013
94537520800575
101300021013003
11461376a74609
1218bb524a714b
139578c57397b
1446cc8298a5d
1523c3abc63d8
hex12eaf4a6a0b

1300021013003 has 4 divisors (see below), whose sum is σ = 1306756873368. Its totient is φ = 1293285152640.

The previous prime is 1300021012973. The next prime is 1300021013009. The reversal of 1300021013003 is 3003101200031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1300021013003 - 28 = 1300021012747 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1300021013009) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3367929893 + ... + 3367930278.

It is an arithmetic number, because the mean of its divisors is an integer number (326689218342).

Almost surely, 21300021013003 is an apocalyptic number.

1300021013003 is a deficient number, since it is larger than the sum of its proper divisors (6735860365).

1300021013003 is an equidigital number, since it uses as much as digits as its factorization.

1300021013003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6735860364.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 1300021013003 its reverse (3003101200031), we get a palindrome (4303122213034).

The spelling of 1300021013003 in words is "one trillion, three hundred billion, twenty-one million, thirteen thousand, three".

Divisors: 1 193 6735860171 1300021013003