130002310100113 has 4 divisors (see below), whose sum is σ = 141820701927408. Its totient is φ = 118183918272820.

The previous prime is 130002310100101. The next prime is 130002310100137. The reversal of 130002310100113 is 311001013200031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130002310100113 - 2⁴¹ = 127803286844561 is a prime.

It is a super-2 number, since 2×130002310100113² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130002317100113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5909195913631 + ... + 5909195913652.

It is an arithmetic number, because the mean of its divisors is an integer number (35455175481852).

Almost surely, 2^{130002310100113} is an apocalyptic number.

It is an amenable number.

130002310100113 is a deficient number, since it is larger than the sum of its proper divisors (11818391827295).

130002310100113 is a wasteful number, since it uses less digits than its factorization.

130002310100113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11818391827294.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 130002310100113 its reverse (311001013200031), we get a palindrome (441003323300144).

The spelling of 130002310100113 in words is "one hundred thirty trillion, two billion, three hundred ten million, one hundred thousand, one hundred thirteen".