130002311320001 has 4 divisors (see below), whose sum is σ = 136844538231600. Its totient is φ = 123160084408404.

The previous prime is 130002311319997. The next prime is 130002311320003. The reversal of 130002311320001 is 100023113200031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130002311320001 - 2² = 130002311319997 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130002311320003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3421113455771 + ... + 3421113455808.

It is an arithmetic number, because the mean of its divisors is an integer number (34211134557900).

Almost surely, 2^{130002311320001} is an apocalyptic number.

It is an amenable number.

130002311320001 is a deficient number, since it is larger than the sum of its proper divisors (6842226911599).

130002311320001 is an equidigital number, since it uses as much as digits as its factorization.

130002311320001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6842226911598.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 130002311320001 its reverse (100023113200031), we get a palindrome (230025424520032).

The spelling of 130002311320001 in words is "one hundred thirty trillion, two billion, three hundred eleven million, three hundred twenty thousand, one".