1300032311131 has 8 divisors (see below), whose sum is σ = 1305155623824. Its totient is φ = 1294909501440.

The previous prime is 1300032311129. The next prime is 1300032311167. The reversal of 1300032311131 is 1311132300031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1300032311131 - 2¹ = 1300032311129 is a prime.

It is a super-2 number, since 2×1300032311131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1300032311099 and 1300032311108.

It is not an unprimeable number, because it can be changed into a prime (1300032311231) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5558176 + ... + 5787346.

It is an arithmetic number, because the mean of its divisors is an integer number (163144452978).

Almost surely, 2^{1300032311131} is an apocalyptic number.

1300032311131 is a deficient number, since it is larger than the sum of its proper divisors (5123312693).

1300032311131 is a wasteful number, since it uses less digits than its factorization.

1300032311131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 251501.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1300032311131 its reverse (1311132300031), we get a palindrome (2611164611162).

The spelling of 1300032311131 in words is "one trillion, three hundred billion, thirty-two million, three hundred eleven thousand, one hundred thirty-one".