130003345 has 4 divisors (see below), whose sum is σ = 156004020. Its totient is φ = 104002672.

The previous prime is 130003303. The next prime is 130003351. The reversal of 130003345 is 543300031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 543300031 = 127 ⋅4277953.

It can be written as a sum of positive squares in 2 ways, for example, as 69022864 + 60980481 = 8308^2 + 7809^2 .

It is a cyclic number.

It is not a de Polignac number, because 130003345 - 2⁷ = 130003217 is a prime.

It is a super-2 number, since 2×130003345² = 33801739422378050, which contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13000330 + ... + 13000339.

It is an arithmetic number, because the mean of its divisors is an integer number (39001005).

Almost surely, 2^130003345 is an apocalyptic number.

It is an amenable number.

130003345 is a deficient number, since it is larger than the sum of its proper divisors (26000675).

130003345 is an equidigital number, since it uses as much as digits as its factorization.

130003345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26000674.

The product of its (nonzero) digits is 540, while the sum is 19.

The square root of 130003345 is about 11401.9009380015. The cubic root of 130003345 is about 506.5840467680.

Adding to 130003345 its reverse (543300031), we get a palindrome (673303376).

It can be divided in two parts, 1300033 and 45, that added together give a triangular number (1300078 = T₁₆₁₂).

The spelling of 130003345 in words is "one hundred thirty million, three thousand, three hundred forty-five".