130004340001 has 8 divisors (see below), whose sum is σ = 134068977000. Its totient is φ = 125982264960.

The previous prime is 130004339999. The next prime is 130004340013. The reversal of 130004340001 is 100043400031.

It can be written as a sum of positive squares in 4 ways, for example, as 1445520400 + 128558819601 = 38020^2 + 358551^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130004340001 - 2¹ = 130004339999 is a prime.

It is a super-2 number, since 2×130004340001² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130004340041) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10634286 + ... + 10646503.

It is an arithmetic number, because the mean of its divisors is an integer number (16758622125).

Almost surely, 2^130004340001 is an apocalyptic number.

It is an amenable number.

130004340001 is a deficient number, since it is larger than the sum of its proper divisors (4064636999).

130004340001 is a wasteful number, since it uses less digits than its factorization.

130004340001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21280979.

The product of its (nonzero) digits is 144, while the sum is 16.

Adding to 130004340001 its reverse (100043400031), we get a palindrome (230047740032).

The spelling of 130004340001 in words is "one hundred thirty billion, four million, three hundred forty thousand, one".