Search a number
-
+
13000443 = 34333481
BaseRepresentation
bin110001100101…
…111011111011
3220110111020220
4301211323323
511312003233
61142351123
7215334111
oct61457373
926414226
1013000443
11737a475
12442b4a3
132902491
141a25ab1
15121beb3
hexc65efb

13000443 has 4 divisors (see below), whose sum is σ = 17333928. Its totient is φ = 8666960.

The previous prime is 13000411. The next prime is 13000457. The reversal of 13000443 is 34400031.

13000443 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34400031 = 311466677.

It is a cyclic number.

It is not a de Polignac number, because 13000443 - 25 = 13000411 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13000483) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2166738 + ... + 2166743.

It is an arithmetic number, because the mean of its divisors is an integer number (4333482).

Almost surely, 213000443 is an apocalyptic number.

13000443 is a deficient number, since it is larger than the sum of its proper divisors (4333485).

13000443 is an equidigital number, since it uses as much as digits as its factorization.

13000443 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4333484.

The product of its (nonzero) digits is 144, while the sum is 15.

The square root of 13000443 is about 3605.6127079874. The cubic root of 13000443 is about 235.1361396168.

Adding to 13000443 its reverse (34400031), we get a palindrome (47400474).

The spelling of 13000443 in words is "thirteen million, four hundred forty-three", and thus it is an aban number.

Divisors: 1 3 4333481 13000443