130005113374153 has 4 divisors (see below), whose sum is σ = 132208589872080. Its totient is φ = 127801636876228.

The previous prime is 130005113374139. The next prime is 130005113374163. The reversal of 130005113374153 is 351473311500031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130005113374153 - 2¹³ = 130005113365961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130005113374163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1101738248875 + ... + 1101738248992.

It is an arithmetic number, because the mean of its divisors is an integer number (33052147468020).

Almost surely, 2^{130005113374153} is an apocalyptic number.

It is an amenable number.

130005113374153 is a deficient number, since it is larger than the sum of its proper divisors (2203476497927).

130005113374153 is an equidigital number, since it uses as much as digits as its factorization.

130005113374153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2203476497926.

The product of its (nonzero) digits is 56700, while the sum is 37.

Adding to 130005113374153 its reverse (351473311500031), we get a palindrome (481478424874184).

The spelling of 130005113374153 in words is "one hundred thirty trillion, five billion, one hundred thirteen million, three hundred seventy-four thousand, one hundred fifty-three".