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130009924003 = 1271023700189
BaseRepresentation
bin111100100010100110…
…0100000000110100011
3110102120121121102210111
41321011030200012203
54112230020032003
6135420431512151
712251524056211
oct1710514400643
9412517542714
10130009924003
1150156238193
1221244088657
13c34bc6a91b
14641492dcb1
1535adb73e6d
hex1e453201a3

130009924003 has 4 divisors (see below), whose sum is σ = 131033624320. Its totient is φ = 128986223688.

The previous prime is 130009923977. The next prime is 130009924063. The reversal of 130009924003 is 300429900031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130009924003 - 213 = 130009915811 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130009924063) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 511849968 + ... + 511850221.

It is an arithmetic number, because the mean of its divisors is an integer number (32758406080).

Almost surely, 2130009924003 is an apocalyptic number.

130009924003 is a deficient number, since it is larger than the sum of its proper divisors (1023700317).

130009924003 is a wasteful number, since it uses less digits than its factorization.

130009924003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1023700316.

The product of its (nonzero) digits is 5832, while the sum is 31.

The spelling of 130009924003 in words is "one hundred thirty billion, nine million, nine hundred twenty-four thousand, three".

Divisors: 1 127 1023700189 130009924003