1300100133323 has 4 divisors (see below), whose sum is σ = 1300679761128. Its totient is φ = 1299520505520.

The previous prime is 1300100133313. The next prime is 1300100133341. The reversal of 1300100133323 is 3233310010031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1300100133323 - 2⁴ = 1300100133307 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1300100133295 and 1300100133304.

It is not an unprimeable number, because it can be changed into a prime (1300100133313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 289810538 + ... + 289815023.

It is an arithmetic number, because the mean of its divisors is an integer number (325169940282).

Almost surely, 2^{1300100133323} is an apocalyptic number.

1300100133323 is a deficient number, since it is larger than the sum of its proper divisors (579627805).

1300100133323 is an equidigital number, since it uses as much as digits as its factorization.

1300100133323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 579627804.

The product of its (nonzero) digits is 486, while the sum is 20.

Adding to 1300100133323 its reverse (3233310010031), we get a palindrome (4533410143354).

The spelling of 1300100133323 in words is "one trillion, three hundred billion, one hundred million, one hundred thirty-three thousand, three hundred twenty-three".