1300100200033 has 8 divisors (see below), whose sum is σ = 1320449247360. Its totient is φ = 1279807757760.

The previous prime is 1300100200031. The next prime is 1300100200037. The reversal of 1300100200033 is 3300020010031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1300100200033 - 2¹ = 1300100200031 is a prime.

It is a super-2 number, since 2×1300100200033² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1300100199986 and 1300100200022.

It is not an unprimeable number, because it can be changed into a prime (1300100200031) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14104968 + ... + 14196841.

It is an arithmetic number, because the mean of its divisors is an integer number (165056155920).

Almost surely, 2^{1300100200033} is an apocalyptic number.

It is an amenable number.

1300100200033 is a deficient number, since it is larger than the sum of its proper divisors (20349047327).

1300100200033 is an equidigital number, since it uses as much as digits as its factorization.

1300100200033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28302527.

The product of its (nonzero) digits is 54, while the sum is 13.

Adding to 1300100200033 its reverse (3300020010031), we get a palindrome (4600120210064).

The spelling of 1300100200033 in words is "one trillion, three hundred billion, one hundred million, two hundred thousand, thirty-three".