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130010022433 = 2311814786291
BaseRepresentation
bin111100100010100110…
…0111000001000100001
3110102120121210102211001
41321011030320020201
54112230031204213
6135420433552001
712251524646164
oct1710514701041
9412517712731
10130010022433
11501562a5135
1221244115601
13c34bca3675
146414957adb
1535adb931dd
hex1e45338221

130010022433 has 8 divisors (see below), whose sum is σ = 135777531456. Its totient is φ = 124252088400.

The previous prime is 130010022427. The next prime is 130010022449. The reversal of 130010022433 is 334220010031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130010022433 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 130010022433.

It is not an unprimeable number, because it can be changed into a prime (130010022413) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2365983 + ... + 2420308.

It is an arithmetic number, because the mean of its divisors is an integer number (16972191432).

Almost surely, 2130010022433 is an apocalyptic number.

It is an amenable number.

130010022433 is a deficient number, since it is larger than the sum of its proper divisors (5767509023).

130010022433 is a wasteful number, since it uses less digits than its factorization.

130010022433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4787495.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 130010022433 its reverse (334220010031), we get a palindrome (464230032464).

The spelling of 130010022433 in words is "one hundred thirty billion, ten million, twenty-two thousand, four hundred thirty-three".

Divisors: 1 23 1181 27163 4786291 110084693 5652609671 130010022433