Base | Representation |
---|---|
bin | 10010111010110100000… |
… | …100100111001010001011 |
3 | 11121021210021211112101110 |
4 | 102322310010213022023 |
5 | 132300101403344433 |
6 | 2433131441221403 |
7 | 162633502062243 |
oct | 22726404471213 |
9 | 4537707745343 |
10 | 1300101231243 |
11 | 461408284781 |
12 | 18bb75331863 |
13 | 957a307c499 |
14 | 46cd4bbab23 |
15 | 23c42c6e963 |
hex | 12eb412728b |
1300101231243 has 4 divisors (see below), whose sum is σ = 1733468308328. Its totient is φ = 866734154160.
The previous prime is 1300101231241. The next prime is 1300101231257. The reversal of 1300101231243 is 3421321010031.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1300101231243 - 21 = 1300101231241 is a prime.
It is a super-2 number, since 2×13001012312432 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1300101231241) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 216683538538 + ... + 216683538543.
It is an arithmetic number, because the mean of its divisors is an integer number (433367077082).
Almost surely, 21300101231243 is an apocalyptic number.
1300101231243 is a deficient number, since it is larger than the sum of its proper divisors (433367077085).
1300101231243 is an equidigital number, since it uses as much as digits as its factorization.
1300101231243 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 433367077084.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 1300101231243 its reverse (3421321010031), we get a palindrome (4721422241274).
The spelling of 1300101231243 in words is "one trillion, three hundred billion, one hundred one million, two hundred thirty-one thousand, two hundred forty-three".
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