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13001020121 = 15186099471
BaseRepresentation
bin11000001101110101…
…11101001011011001
31020120001201020210202
430012322331023121
5203111230120441
65550024551545
7640114563515
oct140672751331
936501636722
1013001020121
115571811931
12262a0225b5
1312c266b11b
148b4953145
155115a419b
hex306ebd2d9

13001020121 has 4 divisors (see below), whose sum is σ = 13087119744. Its totient is φ = 12914920500.

The previous prime is 13001020069. The next prime is 13001020133. The reversal of 13001020121 is 12102010031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13001020121 - 222 = 12996825817 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13001020321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43049585 + ... + 43049886.

It is an arithmetic number, because the mean of its divisors is an integer number (3271779936).

Almost surely, 213001020121 is an apocalyptic number.

It is an amenable number.

13001020121 is a deficient number, since it is larger than the sum of its proper divisors (86099623).

13001020121 is an equidigital number, since it uses as much as digits as its factorization.

13001020121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 86099622.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 13001020121 its reverse (12102010031), we get a palindrome (25103030152).

The spelling of 13001020121 in words is "thirteen billion, one million, twenty thousand, one hundred twenty-one".

Divisors: 1 151 86099471 13001020121