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13001021033 = 7111312988033
BaseRepresentation
bin11000001101110101…
…11101011001101001
31020120001201022001112
430012322331121221
5203111230133113
65550025000105
7640114566260
oct140672753151
936501638045
1013001021033
115571812590
12262a023035
1312c266b670
148b49535d7
155115a45a8
hex306ebd669

13001021033 has 16 divisors (see below), whose sum is σ = 17455917696. Its totient is φ = 9351383040.

The previous prime is 13001021023. The next prime is 13001021053. The reversal of 13001021033 is 33012010031.

It is a cyclic number.

It is not a de Polignac number, because 13001021033 - 26 = 13001020969 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13001020999 and 13001021017.

It is not an unprimeable number, because it can be changed into a prime (13001021023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6493016 + ... + 6495017.

It is an arithmetic number, because the mean of its divisors is an integer number (1090994856).

Almost surely, 213001021033 is an apocalyptic number.

13001021033 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

13001021033 is a deficient number, since it is larger than the sum of its proper divisors (4454896663).

13001021033 is a wasteful number, since it uses less digits than its factorization.

13001021033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12988064.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 13001021033 its reverse (33012010031), we get a palindrome (46013031064).

The spelling of 13001021033 in words is "thirteen billion, one million, twenty-one thousand, thirty-three".

Divisors: 1 7 11 13 77 91 143 1001 12988033 90916231 142868363 168844429 1000078541 1181911003 1857288719 13001021033