Base | Representation |
---|---|
bin | 10010111010110100100… |
… | …110011100011010010001 |
3 | 11121021210220112010012010 |
4 | 102322310212130122101 |
5 | 132300111141200423 |
6 | 2433132355253133 |
7 | 162633640341066 |
oct | 22726446343221 |
9 | 4537726463163 |
10 | 1300110100113 |
11 | 461412292020 |
12 | 18bb782aa1a9 |
13 | 957a4b66236 |
14 | 46cd6048c6d |
15 | 23c43922693 |
hex | 12eb499c691 |
1300110100113 has 16 divisors (see below), whose sum is σ = 1903592881152. Its totient is φ = 782727330000.
The previous prime is 1300110100103. The next prime is 1300110100151. The reversal of 1300110100113 is 3110010110031.
It is not a de Polignac number, because 1300110100113 - 220 = 1300109051537 is a prime.
It is a super-2 number, since 2×13001101001132 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1300110100103) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 130449573 + ... + 130459538.
It is an arithmetic number, because the mean of its divisors is an integer number (118974555072).
Almost surely, 21300110100113 is an apocalyptic number.
It is an amenable number.
1300110100113 is a deficient number, since it is larger than the sum of its proper divisors (603482781039).
1300110100113 is a wasteful number, since it uses less digits than its factorization.
1300110100113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 260909276.
The product of its (nonzero) digits is 9, while the sum is 12.
Adding to 1300110100113 its reverse (3110010110031), we get a palindrome (4410120210144).
The spelling of 1300110100113 in words is "one trillion, three hundred billion, one hundred ten million, one hundred thousand, one hundred thirteen".
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