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1300113230113 = 21291048758231
BaseRepresentation
bin10010111010110100110…
…010011000100100100001
311121021211010102010202001
4102322310302120210201
5132300112441330423
62433132550324001
7162634006055335
oct22726462304441
94537733363661
101300113230113
1146141402a6a5
1218bb79359601
13957a56c0ac9
1446cd66217c5
1523c43d3ecad
hex12eb4c98921

1300113230113 has 8 divisors (see below), whose sum is σ = 1300870270080. Its totient is φ = 1299356331840.

The previous prime is 1300113230089. The next prime is 1300113230131. The reversal of 1300113230113 is 3110323110031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1300113230113 is a prime.

It is a super-2 number, since 2×13001132301132 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1300113230183) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 22297708 + ... + 22355938.

It is an arithmetic number, because the mean of its divisors is an integer number (162608783760).

Almost surely, 21300113230113 is an apocalyptic number.

It is an amenable number.

1300113230113 is a deficient number, since it is larger than the sum of its proper divisors (757039967).

1300113230113 is a wasteful number, since it uses less digits than its factorization.

1300113230113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 70847.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1300113230113 its reverse (3110323110031), we get a palindrome (4410436340144).

The spelling of 1300113230113 in words is "one trillion, three hundred billion, one hundred thirteen million, two hundred thirty thousand, one hundred thirteen".

Divisors: 1 2129 10487 58231 22326823 123973799 610668497 1300113230113