13001132411 has 4 divisors (see below), whose sum is σ = 13184247024. Its totient is φ = 12818017800.

The previous prime is 13001132399. The next prime is 13001132423. The reversal of 13001132411 is 11423110031.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (13001132399) and next prime (13001132423).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13001132411 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13001132411.

It is not an unprimeable number, because it can be changed into a prime (13001132471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 91557200 + ... + 91557341.

It is an arithmetic number, because the mean of its divisors is an integer number (3296061756).

Almost surely, 2^13001132411 is an apocalyptic number.

13001132411 is a deficient number, since it is larger than the sum of its proper divisors (183114613).

13001132411 is an equidigital number, since it uses as much as digits as its factorization.

13001132411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 183114612.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 13001132411 its reverse (11423110031), we get a palindrome (24424242442).

The spelling of 13001132411 in words is "thirteen billion, one million, one hundred thirty-two thousand, four hundred eleven".