13001202131131 has 4 divisors (see below), whose sum is σ = 13004952120792. Its totient is φ = 12997452141472.

The previous prime is 13001202131077. The next prime is 13001202131153. The reversal of 13001202131131 is 13113120210031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13001202131131 is a prime.

It is a super-2 number, since 2×13001202131131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13001202131099 and 13001202131108.

It is not an unprimeable number, because it can be changed into a prime (13001202131231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1874989630 + ... + 1874996563.

It is an arithmetic number, because the mean of its divisors is an integer number (3251238030198).

Almost surely, 2^{13001202131131} is an apocalyptic number.

13001202131131 is a deficient number, since it is larger than the sum of its proper divisors (3749989661).

13001202131131 is an equidigital number, since it uses as much as digits as its factorization.

13001202131131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3749989660.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 13001202131131 its reverse (13113120210031), we get a palindrome (26114322341162).

The spelling of 13001202131131 in words is "thirteen trillion, one billion, two hundred two million, one hundred thirty-one thousand, one hundred thirty-one".