13001211320131 has 4 divisors (see below), whose sum is σ = 13566481377552. Its totient is φ = 12435941262712.

The previous prime is 13001211320113. The next prime is 13001211320183. The reversal of 13001211320131 is 13102311210031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13001211320131 - 2⁵ = 13001211320099 is a prime.

It is a super-2 number, since 2×13001211320131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13001211320099 and 13001211320108.

It is not an unprimeable number, because it can be changed into a prime (13001211320101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 282635028676 + ... + 282635028721.

It is an arithmetic number, because the mean of its divisors is an integer number (3391620344388).

Almost surely, 2^{13001211320131} is an apocalyptic number.

13001211320131 is a deficient number, since it is larger than the sum of its proper divisors (565270057421).

13001211320131 is an equidigital number, since it uses as much as digits as its factorization.

13001211320131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 565270057420.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 13001211320131 its reverse (13102311210031), we get a palindrome (26103522530162).

The spelling of 13001211320131 in words is "thirteen trillion, one billion, two hundred eleven million, three hundred twenty thousand, one hundred thirty-one".