Base | Representation |
---|---|
bin | 111100100010101100… |
… | …0001100010000011011 |
3 | 110102120211101010102021 |
4 | 1321011120030100123 |
5 | 4112231311112233 |
6 | 135421021315311 |
7 | 12251562111352 |
oct | 1710530142033 |
9 | 412524333367 |
10 | 130012988443 |
11 | 50157a40588 |
12 | 21245105b37 |
13 | c34c7a16c0 |
14 | 64150ca999 |
15 | 35ae07be2d |
hex | 1e4560c41b |
130012988443 has 4 divisors (see below), whose sum is σ = 140013987568. Its totient is φ = 120011989320.
The previous prime is 130012988437. The next prime is 130012988477. The reversal of 130012988443 is 344889210031.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 344889210031 = 311 ⋅1108968521.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130012988443 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 130012988443.
It is not an unprimeable number, because it can be changed into a prime (130012988423) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5000499543 + ... + 5000499568.
It is an arithmetic number, because the mean of its divisors is an integer number (35003496892).
Almost surely, 2130012988443 is an apocalyptic number.
130012988443 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
130012988443 is a deficient number, since it is larger than the sum of its proper divisors (10000999125).
130012988443 is a wasteful number, since it uses less digits than its factorization.
130012988443 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10000999124.
The product of its (nonzero) digits is 165888, while the sum is 43.
The spelling of 130012988443 in words is "one hundred thirty billion, twelve million, nine hundred eighty-eight thousand, four hundred forty-three".
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