Base | Representation |
---|---|
bin | 11000001101111000… |
… | …00001100101011001 |
3 | 1020120002020111011020 |
4 | 30012330001211121 |
5 | 203111313102223 |
6 | 5550034553053 |
7 | 640120141431 |
oct | 140674014531 |
9 | 36502214136 |
10 | 13001300313 |
11 | 55719933a1 |
12 | 262a138789 |
13 | 12c2738811 |
14 | 8b49c72c1 |
15 | 51160c1e3 |
hex | 306f01959 |
13001300313 has 4 divisors (see below), whose sum is σ = 17335067088. Its totient is φ = 8667533540.
The previous prime is 13001300311. The next prime is 13001300327. The reversal of 13001300313 is 31300310031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13001300313 - 21 = 13001300311 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13001300292 and 13001300301.
It is not an unprimeable number, because it can be changed into a prime (13001300311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2166883383 + ... + 2166883388.
It is an arithmetic number, because the mean of its divisors is an integer number (4333766772).
Almost surely, 213001300313 is an apocalyptic number.
It is an amenable number.
13001300313 is a deficient number, since it is larger than the sum of its proper divisors (4333766775).
13001300313 is an equidigital number, since it uses as much as digits as its factorization.
13001300313 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4333766774.
The product of its (nonzero) digits is 81, while the sum is 15.
Adding to 13001300313 its reverse (31300310031), we get a palindrome (44301610344).
The spelling of 13001300313 in words is "thirteen billion, one million, three hundred thousand, three hundred thirteen".
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