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130013104001 = 1111819373091
BaseRepresentation
bin111100100010101100…
…0101000011110000001
3110102120211120222221012
41321011120220132001
54112231323312001
6135421024010305
712251563102304
oct1710530503601
9412524528835
10130013104001
115015800a390
1221245160995
13c34c812191
14641511ab3b
1535ae0a12bb
hex1e45628781

130013104001 has 4 divisors (see below), whose sum is σ = 141832477104. Its totient is φ = 118193730900.

The previous prime is 130013103971. The next prime is 130013104003. The reversal of 130013104001 is 100401310031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130013104001 - 230 = 128939362177 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130013104003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5909686535 + ... + 5909686556.

It is an arithmetic number, because the mean of its divisors is an integer number (35458119276).

Almost surely, 2130013104001 is an apocalyptic number.

130013104001 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

130013104001 is a deficient number, since it is larger than the sum of its proper divisors (11819373103).

130013104001 is a wasteful number, since it uses less digits than its factorization.

130013104001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11819373102.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 130013104001 its reverse (100401310031), we get a palindrome (230414414032).

The spelling of 130013104001 in words is "one hundred thirty billion, thirteen million, one hundred four thousand, one".

Divisors: 1 11 11819373091 130013104001