13001425554001 has 4 divisors (see below), whose sum is σ = 13001498574912. Its totient is φ = 13001352533092.

The previous prime is 13001425553947. The next prime is 13001425554023. The reversal of 13001425554001 is 10045552410031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13001425554001 - 2¹¹ = 13001425551953 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13001425551001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36242725 + ... + 36599698.

It is an arithmetic number, because the mean of its divisors is an integer number (3250374643728).

Almost surely, 2^{13001425554001} is an apocalyptic number.

It is an amenable number.

13001425554001 is a deficient number, since it is larger than the sum of its proper divisors (73020911).

13001425554001 is an equidigital number, since it uses as much as digits as its factorization.

13001425554001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 73020910.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 13001425554001 its reverse (10045552410031), we get a palindrome (23046977964032).

The spelling of 13001425554001 in words is "thirteen trillion, one billion, four hundred twenty-five million, five hundred fifty-four thousand, one".