13001433321411 has 6 divisors (see below), whose sum is σ = 18779848130940. Its totient is φ = 8667622214268.

The previous prime is 13001433321391. The next prime is 13001433321449. The reversal of 13001433321411 is 11412333410031.

13001433321411 is a `hidden beast` number, since 1 + 3 + 0 + 0 + 1 + 433 + 3 + 214 + 11 = 666.

13001433321411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 13001433321411 - 2¹⁵ = 13001433288643 is a prime.

It is a super-2 number, since 2×13001433321411² (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13001433321011) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 722301851181 + ... + 722301851198.

It is an arithmetic number, because the mean of its divisors is an integer number (3129974688490).

Almost surely, 2^{13001433321411} is an apocalyptic number.

13001433321411 is a deficient number, since it is larger than the sum of its proper divisors (5778414809529).

13001433321411 is a wasteful number, since it uses less digits than its factorization.

13001433321411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1444603702385 (or 1444603702382 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 27.

Adding to 13001433321411 its reverse (11412333410031), we get a palindrome (24413766731442).

The spelling of 13001433321411 in words is "thirteen trillion, one billion, four hundred thirty-three million, three hundred twenty-one thousand, four hundred eleven".