Search a number
-
+
13002033113 = 31419420423
BaseRepresentation
bin11000001101111101…
…10100011111011001
31020120010121201100222
430012332310133121
5203112010024423
65550102405425
7640126313036
oct140676643731
936503551328
1013002033113
115572343a13
12262a430875
1312c2934224
148b4b3838d
155117043c8
hex306fb47d9

13002033113 has 4 divisors (see below), whose sum is σ = 13421453568. Its totient is φ = 12582612660.

The previous prime is 13002033053. The next prime is 13002033151. The reversal of 13002033113 is 31133020031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31133020031 = 56355298437.

It is a cyclic number.

It is not a de Polignac number, because 13002033113 - 26 = 13002033049 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13002033091 and 13002033100.

It is not an unprimeable number, because it can be changed into a prime (13002033413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 209710181 + ... + 209710242.

It is an arithmetic number, because the mean of its divisors is an integer number (3355363392).

Almost surely, 213002033113 is an apocalyptic number.

It is an amenable number.

13002033113 is a deficient number, since it is larger than the sum of its proper divisors (419420455).

13002033113 is an equidigital number, since it uses as much as digits as its factorization.

13002033113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 419420454.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 13002033113 its reverse (31133020031), we get a palindrome (44135053144).

The spelling of 13002033113 in words is "thirteen billion, two million, thirty-three thousand, one hundred thirteen".

Divisors: 1 31 419420423 13002033113