Base | Representation |
---|---|
bin | 11000001101111101… |
… | …10111011001101011 |
3 | 1020120010122022201112 |
4 | 30012332313121223 |
5 | 203112010420120 |
6 | 5550102540535 |
7 | 640126362560 |
oct | 140676673153 |
9 | 36503568645 |
10 | 13002045035 |
11 | 5572351971 |
12 | 262a43774b |
13 | 12c2939795 |
14 | 8b4b3c867 |
15 | 511707bc5 |
hex | 306fb766b |
13002045035 has 16 divisors (see below), whose sum is σ = 18046215936. Its totient is φ = 8808268128.
The previous prime is 13002045031. The next prime is 13002045103. The reversal of 13002045035 is 53054020031.
It is a cyclic number.
It is not a de Polignac number, because 13002045035 - 22 = 13002045031 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13002045035.
It is not an unprimeable number, because it can be changed into a prime (13002045031) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2234969 + ... + 2240778.
It is an arithmetic number, because the mean of its divisors is an integer number (1127888496).
Almost surely, 213002045035 is an apocalyptic number.
13002045035 is a deficient number, since it is larger than the sum of its proper divisors (5044170901).
13002045035 is an equidigital number, since it uses as much as digits as its factorization.
13002045035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4475842.
The product of its (nonzero) digits is 1800, while the sum is 23.
Adding to 13002045035 its reverse (53054020031), we get a palindrome (66056065066).
The spelling of 13002045035 in words is "thirteen billion, two million, forty-five thousand, thirty-five".
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