1300211440113 has 8 divisors (see below), whose sum is σ = 1835592621408. Its totient is φ = 815818942784.

The previous prime is 1300211440091. The next prime is 1300211440123. The reversal of 1300211440113 is 3110441120031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1300211440113 - 2¹⁰ = 1300211439089 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1300211440113.

It is not an unprimeable number, because it can be changed into a prime (1300211440123) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12747170931 + ... + 12747171032.

It is an arithmetic number, because the mean of its divisors is an integer number (229449077676).

Almost surely, 2^{1300211440113} is an apocalyptic number.

It is an amenable number.

1300211440113 is a deficient number, since it is larger than the sum of its proper divisors (535381181295).

1300211440113 is a wasteful number, since it uses less digits than its factorization.

1300211440113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25494341983.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 1300211440113 its reverse (3110441120031), we get a palindrome (4410652560144).

The spelling of 1300211440113 in words is "one trillion, three hundred billion, two hundred eleven million, four hundred forty thousand, one hundred thirteen".