Base | Representation |
---|---|
bin | 11101100100000011110010… |
… | …000000001100010010100001 |
3 | 122001100220201122202121100001 |
4 | 131210003302000030102201 |
5 | 114020232120342333441 |
6 | 1140310544255500001 |
7 | 36246505162561456 |
oct | 3544036200142241 |
9 | 561326648677301 |
10 | 130021310121121 |
11 | 38479800a07681 |
12 | 126bb001827601 |
13 | 5771c594cc803 |
14 | 24170ca47b82d |
15 | 1007245353731 |
hex | 7640f200c4a1 |
130021310121121 has 4 divisors (see below), whose sum is σ = 133535399583892. Its totient is φ = 126507220658352.
The previous prime is 130021310121077. The next prime is 130021310121239. The reversal of 130021310121121 is 121121013120031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 126271045487521 + 3750264633600 = 11237039^2 + 1936560^2 .
It is a cyclic number.
It is not a de Polignac number, because 130021310121121 - 27 = 130021310120993 is a prime.
It is a super-2 number, since 2×1300213101211212 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130021310121421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1757044731330 + ... + 1757044731403.
It is an arithmetic number, because the mean of its divisors is an integer number (33383849895973).
Almost surely, 2130021310121121 is an apocalyptic number.
It is an amenable number.
130021310121121 is a deficient number, since it is larger than the sum of its proper divisors (3514089462771).
130021310121121 is an equidigital number, since it uses as much as digits as its factorization.
130021310121121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3514089462770.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 130021310121121 its reverse (121121013120031), we get a palindrome (251142323241152).
The spelling of 130021310121121 in words is "one hundred thirty trillion, twenty-one billion, three hundred ten million, one hundred twenty-one thousand, one hundred twenty-one".
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