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13002201110203 = 18077719267639
BaseRepresentation
bin1011110100110100111110…
…0101000001011010111011
31201000222221202021111211121
42331031033211001122323
53201012001441011303
643353043450010111
72511243443623324
oct275151745013273
951028852244747
1013002201110203
114163225618438
12155bab6a16937
137341439b81a6
1432d44a4b144b
1517833ca229bd
hexbd34f9416bb

13002201110203 has 4 divisors (see below), whose sum is σ = 13002920395920. Its totient is φ = 13001481824488.

The previous prime is 13002201110201. The next prime is 13002201110281. The reversal of 13002201110203 is 30201110220031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13002201110203 - 21 = 13002201110201 is a prime.

It is a super-3 number, since 3×130022011102033 (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13002201110201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 359615743 + ... + 359651896.

It is an arithmetic number, because the mean of its divisors is an integer number (3250730098980).

Almost surely, 213002201110203 is an apocalyptic number.

13002201110203 is a deficient number, since it is larger than the sum of its proper divisors (719285717).

13002201110203 is an equidigital number, since it uses as much as digits as its factorization.

13002201110203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 719285716.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 13002201110203 its reverse (30201110220031), we get a palindrome (43203311330234).

The spelling of 13002201110203 in words is "thirteen trillion, two billion, two hundred one million, one hundred ten thousand, two hundred three".

Divisors: 1 18077 719267639 13002201110203