Search a number
-
+
1300220113 = 47914891823
BaseRepresentation
bin100110101111111…
…1100100011010001
310100121121000200111
41031133330203101
510130324020423
6333004121321
744135455123
oct11537744321
93317530614
101300220113
11607a38685
12303536241
131794b421a
14c497b213
157923560d
hex4d7fc8d1

1300220113 has 8 divisors (see below), whose sum is σ = 1304524800. Its totient is φ = 1295923008.

The previous prime is 1300220099. The next prime is 1300220123. The reversal of 1300220113 is 3110220031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1300220113 - 25 = 1300220081 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1300220093 and 1300220102.

It is not an unprimeable number, because it can be changed into a prime (1300220123) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 712320 + ... + 714142.

It is an arithmetic number, because the mean of its divisors is an integer number (163065600).

Almost surely, 21300220113 is an apocalyptic number.

It is an amenable number.

1300220113 is a deficient number, since it is larger than the sum of its proper divisors (4304687).

1300220113 is a wasteful number, since it uses less digits than its factorization.

1300220113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3791.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 1300220113 is about 36058.5650435510. The cubic root of 1300220113 is about 1091.4544769597.

Adding to 1300220113 its reverse (3110220031), we get a palindrome (4410440144).

The spelling of 1300220113 in words is "one billion, three hundred million, two hundred twenty thousand, one hundred thirteen".

Divisors: 1 479 1489 1823 713231 873217 2714447 1300220113