Base | Representation |
---|---|
bin | 11101100100000100100001… |
… | …101100110000100100011011 |
3 | 122001100222210102111120221212 |
4 | 131210010201230300210123 |
5 | 114020240240221130321 |
6 | 1140311155523053335 |
7 | 36246534050350355 |
oct | 3544044154604433 |
9 | 561328712446855 |
10 | 130022110333211 |
11 | 3847a081682888 |
12 | 126bb1a581124b |
13 | 57720562280a5 |
14 | 24171648600d5 |
15 | 100729071d55b |
hex | 764121b3091b |
130022110333211 has 4 divisors (see below), whose sum is σ = 130023364955832. Its totient is φ = 130020855710592.
The previous prime is 130022110333183. The next prime is 130022110333223. The reversal of 130022110333211 is 112333011220031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 130022110333211 - 218 = 130022110071067 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130022110333261) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 627155846 + ... + 627363131.
It is an arithmetic number, because the mean of its divisors is an integer number (32505841238958).
Almost surely, 2130022110333211 is an apocalyptic number.
130022110333211 is a deficient number, since it is larger than the sum of its proper divisors (1254622621).
130022110333211 is a wasteful number, since it uses less digits than its factorization.
130022110333211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1254622620.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 130022110333211 its reverse (112333011220031), we get a palindrome (242355121553242).
The spelling of 130022110333211 in words is "one hundred thirty trillion, twenty-two billion, one hundred ten million, three hundred thirty-three thousand, two hundred eleven".
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