13002211041 has 4 divisors (see below), whose sum is σ = 17336281392. Its totient is φ = 8668140692.

The previous prime is 13002211039. The next prime is 13002211087. The reversal of 13002211041 is 14011220031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14011220031 = 3 ⋅4670406677.

It is a cyclic number.

It is not a de Polignac number, because 13002211041 - 2¹ = 13002211039 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13002211041.

It is not an unprimeable number, because it can be changed into a prime (13002211021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2167035171 + ... + 2167035176.

It is an arithmetic number, because the mean of its divisors is an integer number (4334070348).

Almost surely, 2^13002211041 is an apocalyptic number.

It is an amenable number.

13002211041 is a deficient number, since it is larger than the sum of its proper divisors (4334070351).

13002211041 is an equidigital number, since it uses as much as digits as its factorization.

13002211041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4334070350.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 13002211041 its reverse (14011220031), we get a palindrome (27013431072).

The spelling of 13002211041 in words is "thirteen billion, two million, two hundred eleven thousand, forty-one".