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130024122113 = 671940658539
BaseRepresentation
bin111100100011000001…
…0101010011100000001
3110102121121022202221102
41321012002222130001
54112242133401423
6135422100104145
712252055542134
oct1710602523401
9412547282842
10130024122113
1150163255466
1221248995055
13c351b9c282
14641678821b
1535b002ac28
hex1e460aa701

130024122113 has 4 divisors (see below), whose sum is σ = 131964780720. Its totient is φ = 128083463508.

The previous prime is 130024122103. The next prime is 130024122143. The reversal of 130024122113 is 311221420031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130024122113 - 210 = 130024121089 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (130024122103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 970329203 + ... + 970329336.

It is an arithmetic number, because the mean of its divisors is an integer number (32991195180).

Almost surely, 2130024122113 is an apocalyptic number.

It is an amenable number.

130024122113 is a deficient number, since it is larger than the sum of its proper divisors (1940658607).

130024122113 is an equidigital number, since it uses as much as digits as its factorization.

130024122113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1940658606.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 130024122113 its reverse (311221420031), we get a palindrome (441245542144).

The spelling of 130024122113 in words is "one hundred thirty billion, twenty-four million, one hundred twenty-two thousand, one hundred thirteen".

Divisors: 1 67 1940658539 130024122113