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130025214453003 = 343341738151001
BaseRepresentation
bin11101100100000111011010…
…101110000010010100001011
3122001101021210202110012210120
4131210013122232002110023
5114020313114344444003
61140312431531114323
736250004012054322
oct3544073256022413
9561337722405716
10130025214453003
1138480424898a41
12126bb9112a29a3
13577242c36636c
14241737ac0b0b9
1510073c2ecc853
hex7641dab8250b

130025214453003 has 4 divisors (see below), whose sum is σ = 173366952604008. Its totient is φ = 86683476302000.

The previous prime is 130025214452977. The next prime is 130025214453011. The reversal of 130025214453003 is 300354412520031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130025214453003 - 224 = 130025197675787 is a prime.

It is not an unprimeable number, because it can be changed into a prime (130025214053003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21670869075498 + ... + 21670869075503.

It is an arithmetic number, because the mean of its divisors is an integer number (43341738151002).

Almost surely, 2130025214453003 is an apocalyptic number.

130025214453003 is a deficient number, since it is larger than the sum of its proper divisors (43341738151005).

130025214453003 is an equidigital number, since it uses as much as digits as its factorization.

130025214453003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43341738151004.

The product of its (nonzero) digits is 43200, while the sum is 33.

Adding to 130025214453003 its reverse (300354412520031), we get a palindrome (430379626973034).

The spelling of 130025214453003 in words is "one hundred thirty trillion, twenty-five billion, two hundred fourteen million, four hundred fifty-three thousand, three".

Divisors: 1 3 43341738151001 130025214453003