Search a number
-
+
13002553 = 25151803
BaseRepresentation
bin110001100110…
…011100111001
3220110121011001
4301212130321
511312040203
61142405001
7215343214
oct61463471
926417131
1013002553
117381013
124430761
132903425
141a2677b
15121c91d
hexc66739

13002553 has 4 divisors (see below), whose sum is σ = 13054608. Its totient is φ = 12950500.

The previous prime is 13002551. The next prime is 13002581. The reversal of 13002553 is 35520031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13002553 - 21 = 13002551 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13002553.

It is not an unprimeable number, because it can be changed into a prime (13002551) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25651 + ... + 26152.

It is an arithmetic number, because the mean of its divisors is an integer number (3263652).

Almost surely, 213002553 is an apocalyptic number.

It is an amenable number.

13002553 is a deficient number, since it is larger than the sum of its proper divisors (52055).

13002553 is an equidigital number, since it uses as much as digits as its factorization.

13002553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 52054.

The product of its (nonzero) digits is 450, while the sum is 19.

The square root of 13002553 is about 3605.9052954841. The cubic root of 13002553 is about 235.1488599632.

Adding to 13002553 its reverse (35520031), we get a palindrome (48522584).

The spelling of 13002553 in words is "thirteen million, two thousand, five hundred fifty-three".

Divisors: 1 251 51803 13002553