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1300310134411 = 10312624370237
BaseRepresentation
bin10010111011000000100…
…001100000111010001011
311121022022211220220122211
4102323000201200322023
5132301013343300121
62433204302525551
7162641616530341
oct22730041407213
94538284826584
101300310134411
11461505198822
121900132968b7
1395807433022
1446d14839991
1523c56286ce1
hex12ec0860e8b

1300310134411 has 4 divisors (see below), whose sum is σ = 1312934504752. Its totient is φ = 1287685764072.

The previous prime is 1300310134393. The next prime is 1300310134421. The reversal of 1300310134411 is 1144310130031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1300310134411 - 219 = 1300309610123 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1300310134421) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6312185016 + ... + 6312185221.

It is an arithmetic number, because the mean of its divisors is an integer number (328233626188).

Almost surely, 21300310134411 is an apocalyptic number.

1300310134411 is a deficient number, since it is larger than the sum of its proper divisors (12624370341).

1300310134411 is a wasteful number, since it uses less digits than its factorization.

1300310134411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12624370340.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 1300310134411 its reverse (1144310130031), we get a palindrome (2444620264442).

The spelling of 1300310134411 in words is "one trillion, three hundred billion, three hundred ten million, one hundred thirty-four thousand, four hundred eleven".

Divisors: 1 103 12624370237 1300310134411