13003111041 has 4 divisors (see below), whose sum is σ = 17337481392. Its totient is φ = 8668740692.

The previous prime is 13003111013. The next prime is 13003111049. The reversal of 13003111041 is 14011130031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13003111041 - 2²⁷ = 12868893313 is a prime.

It is a super-2 number, since 2×13003111041² (a number of 21 digits) contains 22 as substring.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 13003111041.

It is not an unprimeable number, because it can be changed into a prime (13003111049) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2167185171 + ... + 2167185176.

It is an arithmetic number, because the mean of its divisors is an integer number (4334370348).

Almost surely, 2^13003111041 is an apocalyptic number.

It is an amenable number.

13003111041 is a deficient number, since it is larger than the sum of its proper divisors (4334370351).

13003111041 is an equidigital number, since it uses as much as digits as its factorization.

13003111041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4334370350.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 13003111041 its reverse (14011130031), we get a palindrome (27014241072).

The spelling of 13003111041 in words is "thirteen billion, three million, one hundred eleven thousand, forty-one".