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130031252635 = 527919317897
BaseRepresentation
bin111100100011001110…
…1110111010010011011
3110102122002202001011211
41321012131313102123
54112301000041020
6135422513003551
712252203260624
oct1710635672233
9412562661154
10130031252635
1150167285759
122124b2535b7
13c3534c7a0b
1464176c2a4b
1535b098885a
hex1e4677749b

130031252635 has 8 divisors (see below), whose sum is σ = 156093427296. Its totient is φ = 103987719360.

The previous prime is 130031252627. The next prime is 130031252639. The reversal of 130031252635 is 536252130031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 130031252635 - 23 = 130031252627 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130031252597 and 130031252606.

It is not an unprimeable number, because it can be changed into a prime (130031252639) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4644994 + ... + 4672903.

It is an arithmetic number, because the mean of its divisors is an integer number (19511678412).

Almost surely, 2130031252635 is an apocalyptic number.

130031252635 is a deficient number, since it is larger than the sum of its proper divisors (26062174661).

130031252635 is an equidigital number, since it uses as much as digits as its factorization.

130031252635 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9320693.

The product of its (nonzero) digits is 16200, while the sum is 31.

Adding to 130031252635 its reverse (536252130031), we get a palindrome (666283382666).

The spelling of 130031252635 in words is "one hundred thirty billion, thirty-one million, two hundred fifty-two thousand, six hundred thirty-five".

Divisors: 1 5 2791 13955 9317897 46589485 26006250527 130031252635